PlaySpectrum

Helper · book companion path

Prior: Exp, log & light growth · Next: Kap 2 wrap · Shelf: Kurs 4

Math / Helper companion / Derivative apps

Uncut · book companion · ~108–120

Spend f′ on peaks, valleys, sketch

Graphs & max/min

Score 0 / 100

The slope tool is useless if it never answers a job. Climb: where f′ is zero or undefined (candidates) → read the sign of f′ (or f″) to classify peaks and valleys → sketch with those landmarks. Uses differentiation tools already earned — not a brand-new chapter dump. (extrempunkter · max/min · teckenschema)

Vortex

V1 — Candidates where slope vanishes.

Builds on: f′ as a function (intro + later rule tools).

Tool gained: critical points — solve f′(x) = 0 (and note where f′ undefined in the domain).

  1. Principle. At a smooth local peak or valley the tangent is flat — so f′ = 0 is the first place to look. Corners/cusps can also be candidates where f′ fails.
  2. Model. Find x in the domain with f′(x) = 0 or f′ undefined; these are critical numbers.
  3. Prediction / Answer. f(x) = x³ − 3x → f′ = 3x² − 3 = 0 at x = ±1. Those two x-values are the candidates for local max/min.
Vortex

V2 — Classify with sign of f′ (or f″).

Builds on: critical points (V1) + ability to evaluate/sign f′.

Tool gained: first-derivative sign chart (and optional second-derivative test) to label local max/min.

  1. Principle. If slope flips +→−, you rode over a peak; −→+ is a valley. Alternatively f″(c) < 0 at a critical point suggests a local max, > 0 a local min (when f″ exists and ≠ 0).
  2. Model. Sign chart of f′ on intervals around critical points; or test f″(c).
  3. Prediction / Answer. For f(x) = x³ − 3x: f″(x) = 6x → f″(1) = 6 > 0 local min; f″(−1) = −6 < 0 local max. Values f(−1)=2, f(1)=−2.
Vortex

V3 — Closed interval / job: pick the best value.

Builds on: classify critical points (V2) — compare also endpoints when the domain is closed.

Tool gained: extreme-value check — candidates + endpoints → choose global max/min on a closed interval (or state open-domain limits).

  1. Principle. A real job often has a allowed window of x. The best and worst values occur at critical points inside or at the ends of that window.
  2. Model. On [a,b]: evaluate f at critical points in (a,b) and at a,b; pick largest/smallest.
  3. Prediction / Answer. Fence length 40 m for a rectangular pen against a wall: maximize area A(x). Critical point from A′=0 plus domain ends — classic transfer of the same tool.

1. Poor dump → rewrite

Poor explanation

Book dump: “set f′=0 to find max/min” with no check of sign or endpoints. Our rewrite: candidates from f′, then classify, then compare what the job’s domain actually allows.

Tool · weapon

Weapons: f′=0 candidates → sign/f″ classify → endpoints for global on a closed interval. Next: Kap 2 wrap — mixed apps & light DE.

2. Hands-on — cubic landmark

f(x) = x³ − 3x. Watch f′ change sign around the critical points ±1.

…

3. Fake → real

Fake → real

Fake

“Find the local extrema of f(x)=x³−3x.” No reason to care.

Real

A path’s height model is h(x)=x³−3x on a trail map unit. Local max at x=−1 (height 2) and local min at x=1 (height −2) mark rest spots and a dip — same calculus, now route planning.

Gate — four, all required

1. Reconstruct: critical points come from…

2. Why classify after finding candidates?

3. Predict: f(x)=x³−3x on [−2,2]. Global max value?

4. Transfer: maximize area with fixed fence — which Tools?